Verified answer

Factor by grouping,

x(4y-5) - 5(4y-5) = (x-5)(4y-5)

You use factoring by grouping.

4xy - 5x - 20y + 25

Look at the first two terms (the 4xy and the 5x). What common factor do they share?? The x.

Look at the second two terms (the 20y and the 25). What common factor do they have? 5

So rewrite the grouped terms, being careful to factor out the negative from the second group...

x(4y - 5) - 5(4y - 5)

Now factor the (4y - 5) from the two terms...

(4y - 5)(x - 5)

Done!

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You could divide the equation up like so...

(4xy - 20y) - (5x + 25)

And that factors to...

4y(x - 5) - 5(x + 5)

Although I'm not completely sure if that's correct. I haven't done math like this for some time.

4xy-5x-20y+25 put in the group by common than factor out

4xy-20y-5x+25

4y(x-5)-5(x-5)

answer iwll be (4y-5)(x-5)

4xy - 5x - 20y + 25 = (4xy-20y) - (5x - 25)

= 4y ( x - 5 ) - 5 ( x -5 )

= (x-5)(4y-5)

4y^2 + 20y + 25 (factor as perfect square trinomial) (2y + 5)(2y + 5) (2y + 5)^2 <===ANSWER Perfect square trinomial: a^2 + 2ab + b^2 = (a + b)(a + b) = (a + b)^2 or a^2 - 2ab + b^2 = (a - b)(a - b) = (a - b)^2

4xy – 5x – 20y + 25 = (4xy – 5x) – (20y – 25)

.............................. = x(4y – 5) – 5(4y – 5)

.............................. = (4y – 5)(x – 5)

4xy-5x-20y+25

(x(4y-5)-5(4y-5))

(x-5)(4y-5)