How do you factor -2x²-20x-48=0 ? I forget how to factor! :(?
Please break it down in STEPS if you are able to.
I used to understand this, but it has been quite awhile! Please help me figure this out, I would very much appreciate it! :)
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-2x²-20x-48=0
-2(x^2+10x+24)= 0
-2(x^2+6x+4x+24)= 0
-2{ x(x+6)+4(x+6) }= 0
-2(x+4) (x+6)
factor -2x²-20x-48=0
first, factor out (-2)
-2 (x^2 +10x +24)
-2 (x +__)(x+__) find 2 nums product = 24, and sum =10 (6and4)
-2 (x+6)(x+4)