given that the ∆H vapor is 40.79 kJ/ moland that the ∆H fusion is 6.01 kJ/mol?I was told to apply Hess' law to this, but I don't understand how it applies... Thank you for your time!. Created by Love2B. science-mathematics-en - chemistry-en

How do I find ∆H sublimation for ice...?

May 2021 2 60 Report

How do I find ∆H sublimation for ice...?

given that the ∆H vapor is 40.79 kJ/ mol

and that the ∆H fusion is 6.01 kJ/mol?

I was told to apply Hess' law to this, but I don't understand how it applies...

Thank you for your time!

"...the enthalpy of sublimation is the sum of the enthalpies of vaporization and fusion." See link.

∆H sub = ∆H fus + ∆H vap

Using Hess's Law:

H2O(s) --> H2O(l) ∆H fus = 6.01 kJ/mol

H2O(l) --> H2O(g) ∆H vap = 40.79 kJ/ mol

------------------------------------------------------------ When you add these algebraically you get your answer.

H2O(s) --> H2O(g) ∆H sub = ?

I'll bet you can figure it out from here. Best to you.