let the sum of the two roots of its auxiliary equation be 94 and the product of the two roots is 2013. solve the DE.
If the two roots of the characteristic equation are k1 and k2, then we are told that:
k1 + k2 = 94 and k1*k2 = 2013.
k2 = 2013/k1
k1 + (2013/k1) - 94 = 0
We know that k1 cannot equal zero (else the product of k1*k2 would be zero), so we can multiply this last equation by k1:
k1^2 - 94*k1 + 2013 = 0
(k1 - 33)(k1 - 61) = 0
k1 = 33 or 61,
Plugging these results into the constraint that k1 + k2 = 94, we find that k2 = 61 or 33, which are the values for k1 we already found.
The solution to the differential equation is then:
y(t) = a*exp(33t) + b*exp(61t)
where a and b are the constants of integration.
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If the two roots of the characteristic equation are k1 and k2, then we are told that:
k1 + k2 = 94 and k1*k2 = 2013.
k2 = 2013/k1
k1 + (2013/k1) - 94 = 0
We know that k1 cannot equal zero (else the product of k1*k2 would be zero), so we can multiply this last equation by k1:
k1^2 - 94*k1 + 2013 = 0
(k1 - 33)(k1 - 61) = 0
k1 = 33 or 61,
Plugging these results into the constraint that k1 + k2 = 94, we find that k2 = 61 or 33, which are the values for k1 we already found.
The solution to the differential equation is then:
y(t) = a*exp(33t) + b*exp(61t)
where a and b are the constants of integration.