The line parallel to y = b + mx through a given point (x₀,y₀) is y = (y₀ - mx₀) + mx.
So the line parallel to y = 20 - 5x through a given point (√5,10) is y = 10+5√5 - 5x.
Using the format of the equation of the line provided in the question. Approximate the value of 10+5√5 if this if required, but it is not mentioned here.
Answers & Comments
The line parallel to y = b + mx through a given point (x₀,y₀) is y = (y₀ - mx₀) + mx.
So the line parallel to y = 20 - 5x through a given point (√5,10) is y = 10+5√5 - 5x.
Using the format of the equation of the line provided in the question. Approximate the value of 10+5√5 if this if required, but it is not mentioned here.
Parallel means same slope.
y = -5x + b
Plug in our known points:
10 = -5(sqrt(5)) + b
b = 21.18
y = -5x + 21.18