Limit question, using (f(x+h)-f(x))/h
Do it in two parts:
The 4x
4(x + h) - 4x all over h
= (4x + 4h - 4x)/h
= 4h/h
= 4 no matter what x is
The 3√x
3√(x + h) - 3√x all over h
Multiply top and bottom by 3√(x + h) + 3√x to rationalize the numerator
The top is now 9(x + h) - 9x = 9x + 9h - 9x = 9h
and the bottom is h(3√(x + h) + 3√x)
Cancel the h's to leave 9 over 3√(x + h) + 3√x and as h → 0, this is 9 over 2•3√x
which when x = 4 is 9 over 2•3•2 = 9/12 = 3/4
so f ' (4) = 4 + 3/4 = 19/4
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Verified answer
Do it in two parts:
The 4x
4(x + h) - 4x all over h
= (4x + 4h - 4x)/h
= 4h/h
= 4 no matter what x is
The 3√x
3√(x + h) - 3√x all over h
Multiply top and bottom by 3√(x + h) + 3√x to rationalize the numerator
The top is now 9(x + h) - 9x = 9x + 9h - 9x = 9h
and the bottom is h(3√(x + h) + 3√x)
Cancel the h's to leave 9 over 3√(x + h) + 3√x and as h → 0, this is 9 over 2•3√x
which when x = 4 is 9 over 2•3•2 = 9/12 = 3/4
so f ' (4) = 4 + 3/4 = 19/4