F(x) = -3/(x+4)
x=-4 is a point of infinite discontinuity
There are no zeros
F(x) has no zeros.
It is discontinuous at x = -4 because x = -4 would lead to a 0 in the denominator.
There are no zeros, as you have a nonzero numerator. You have a vertical asymptote at x = -4 in terms of discontinuity.
Note that f(x) is in the form of a fraction and that its numerator is -3.
The only way a fraction can equal zero is when its numerator is zero.
Since f(x) has a numerator of -3, f(x) will never equal zero. Thus,
f(x) has NO ZEROs. It doesn't cross the x-axis............ANS
Again, since f(x) is a fraction, it can never have zero as a denominator
since that would make it undefined. Therefore,
..........x+4 ≠ 0
..........x ≠ -4
This means there is a DISCONTINUITY AT x=-4..........ANS
(see graph below)
There are no zeros. Discontinuity is when (x+4)=0. Or x=-4
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Answers & Comments
F(x) = -3/(x+4)
x=-4 is a point of infinite discontinuity
There are no zeros
F(x) has no zeros.
It is discontinuous at x = -4 because x = -4 would lead to a 0 in the denominator.
There are no zeros, as you have a nonzero numerator. You have a vertical asymptote at x = -4 in terms of discontinuity.
Note that f(x) is in the form of a fraction and that its numerator is -3.
The only way a fraction can equal zero is when its numerator is zero.
Since f(x) has a numerator of -3, f(x) will never equal zero. Thus,
f(x) has NO ZEROs. It doesn't cross the x-axis............ANS
Again, since f(x) is a fraction, it can never have zero as a denominator
since that would make it undefined. Therefore,
..........x+4 ≠ 0
..........x ≠ -4
This means there is a DISCONTINUITY AT x=-4..........ANS
(see graph below)
There are no zeros. Discontinuity is when (x+4)=0. Or x=-4