since rate law = k[A][B]
so in the slow step both A and B are present ....and mechanism is :-
A + B --------> AB (slow)
AB + A --------> A2B (fast)
here AB is an intermediate .....
does this help ??
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since rate law = k[A][B]
so in the slow step both A and B are present ....and mechanism is :-
A + B --------> AB (slow)
AB + A --------> A2B (fast)
here AB is an intermediate .....
does this help ??