Richard -if you look at the sides of that triangle you will see that it is just an enlarged version of that triangle with sides 1, 2 & rt3 - 9 times bigger, so the angles are 60 and 30 degrees. However, starting from scratch: sinA = 9rt3/18 = rt3/2; cosA = 9/18 = 1/2 and tanA = 9rt3/9 = 1/rt3. CosecA = 1/sinA, secA = 1/cosA and cotA = 1/tanA so I'm sure you can do those yourself. I used A because I can't type theta.
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sin= (9√3)/18 = √3/2
cos= 9/18 = 1/2
tan= (9√3)/9 = √3
csc= 1/sin = 2/√3 = (2√3)/3
sec = 1/cos = 2
cot= 1/tan= 1/√3= (√3)/3
Richard -if you look at the sides of that triangle you will see that it is just an enlarged version of that triangle with sides 1, 2 & rt3 - 9 times bigger, so the angles are 60 and 30 degrees. However, starting from scratch: sinA = 9rt3/18 = rt3/2; cosA = 9/18 = 1/2 and tanA = 9rt3/9 = 1/rt3. CosecA = 1/sinA, secA = 1/cosA and cotA = 1/tanA so I'm sure you can do those yourself. I used A because I can't type theta.