Find the roots of the equation 3x² + 16x = 12? I am so confused!
3x² + 16x = 12 => 3x² + 16x -12=0
(3x -2 ) (x + 6)=0
3x-2=0. Or. X+6=0
X= 2/3 or x=-6
3x2+16x-12=0
X= -6
3*(-6)2+16*(-6)-12=0
see formulas for next time here
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Verified answer
3x² + 16x = 12 => 3x² + 16x -12=0
(3x -2 ) (x + 6)=0
3x-2=0. Or. X+6=0
X= 2/3 or x=-6
3x2+16x-12=0
X= -6
3*(-6)2+16*(-6)-12=0
see formulas for next time here