Then find the magnitude of AB.
A (–7, –2, 4); 8.31
B (–1, –2, 4); 4.58
C (1, –2, 4); 4.58
D (–7, 2, 6); 9.43
To the daddy of your son:
the order triple is
(1, -2, 4)
|AB|=
sqrt(1+4+16)=
sqrt(21)=
4.58
approximately.
Just subtract (-4, 2, 1) from (- 3, 0, 9) to get ((1, - 2, 4). C.
Magnitude is sq rt(1^2 +(-2)^2 + 4^2) = 4.58
C (1,-2,4); 4.58
Subtract the first vector from the second using vector addition to get the triple, then use the pythagorean theorem twice to get the magnitude.
--->
AB = [ 1____-2____4 ]
-->
I AB I = â 21 = 4.58
OPTION C
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Verified answer
To the daddy of your son:
the order triple is
(1, -2, 4)
|AB|=
sqrt(1+4+16)=
sqrt(21)=
4.58
approximately.
Just subtract (-4, 2, 1) from (- 3, 0, 9) to get ((1, - 2, 4). C.
Magnitude is sq rt(1^2 +(-2)^2 + 4^2) = 4.58
C (1,-2,4); 4.58
Subtract the first vector from the second using vector addition to get the triple, then use the pythagorean theorem twice to get the magnitude.
--->
AB = [ 1____-2____4 ]
-->
I AB I = â 21 = 4.58
OPTION C