Find the inverse fucntion, f^-1, of f(x)=(4x)/(√(9x²+4)). Please help me i get confused when there is a root?
I know i have to switch out y for x, but i dont know how to solve for y with the square root. I really need help. Your help will be greatly appreciated.
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'ryabokon6" is correct although I would write it as 2 x / √ (16-9 x²)
To find the inverse function you need to switch "x" with "y" and solve for "y".
answer is f^-1(x) = â((-4x^2) / (9x^2 - 16))
i am pretty sure (because my calc class covered this about two weeks ago) the answer is f(x)^-1=â((x-8)/7) because you would multiply â(9x²+4) to the top and bottom of the fraction to get rid of the square root on the bottom, then it can be broken down because all the numbers in the square root are perfect squares (but that could be wrong...pretty sure you can do that) then distribute and get y by itself...hopefully that helps...hard stuff eh?