3x + 2y = 4
2y = 4 - 3x
y = 2 - 3/2 x
Slope = -3/2
y = mx + b
y = -3/2 x + b
-4 = -3/2 (2) + b
b = -1
Answer...y = -3/2 x - 1
Parallel lines have equal slope, so 1st find the slope of the given line:
3x+2y=4
2y=4-3x
y=-3x/2+2
Use that and the point to find b for the new equation:
y=mx+b
-4 = (-3/2)(2)+b
-4 = -3+b
-1 = b
y = (-3/2)x-1
For the same slope, we keep the same coefficients on x and y.
So we have:
3x + 2y = c
To find c, we plug in the values we have for x and y:
3(2) + 2(-4) = c
6 - 8 = c
-2 = c
So our final equation (in the same form as the original equation) is:
3x + 2y = -2
If you want that in slope-intercept form, solve for y:
2y = -3x - 2
y = (-3/2) x - 1
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Verified answer
3x + 2y = 4
2y = 4 - 3x
y = 2 - 3/2 x
Slope = -3/2
y = mx + b
y = -3/2 x + b
-4 = -3/2 (2) + b
b = -1
Answer...y = -3/2 x - 1
Parallel lines have equal slope, so 1st find the slope of the given line:
3x+2y=4
2y=4-3x
y=-3x/2+2
Slope = -3/2
Use that and the point to find b for the new equation:
y=mx+b
-4 = (-3/2)(2)+b
-4 = -3+b
-1 = b
y = (-3/2)x-1
For the same slope, we keep the same coefficients on x and y.
So we have:
3x + 2y = c
To find c, we plug in the values we have for x and y:
3(2) + 2(-4) = c
6 - 8 = c
-2 = c
So our final equation (in the same form as the original equation) is:
3x + 2y = -2
If you want that in slope-intercept form, solve for y:
3x + 2y = -2
2y = -3x - 2
y = (-3/2) x - 1