3906
8736
19,531
97,656
It is multiplied by 5 everytime
5^x = next # in the sequence (starting at x = 0)
5^0 + 5^1 + 5^2 + 5^3 + 5^4 + 5^5 + 5^6 = 19,531
the sum of the first n terms of a geometric series is:
S = (1 - r^n)/(1-r)
where a is the first term of the series (in this case a = 1) , and r is the common ratio (in this case r = 5), and we are asked to find for n = 7
So...
S = (1 - 5^7)/(1-5)
S = (1 - 78,125) / (-4)
S = (-78,124) / (-4)
S = 19,531
S7 = (1 - (5)^7)/(1 - 5) = (5^7 - 1)/4 = 19,531
this is a geometric series where a₁=1 and r=5
Sn =a₁(qⁿ-1) / q-1
S7= 1*(5^7 -1)5-1 =>5^6/4 => 19531
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Verified answer
It is multiplied by 5 everytime
5^x = next # in the sequence (starting at x = 0)
5^0 + 5^1 + 5^2 + 5^3 + 5^4 + 5^5 + 5^6 = 19,531
the sum of the first n terms of a geometric series is:
S = (1 - r^n)/(1-r)
where a is the first term of the series (in this case a = 1) , and r is the common ratio (in this case r = 5), and we are asked to find for n = 7
So...
S = (1 - r^n)/(1-r)
S = (1 - 5^7)/(1-5)
S = (1 - 78,125) / (-4)
S = (-78,124) / (-4)
S = 19,531
S7 = (1 - (5)^7)/(1 - 5) = (5^7 - 1)/4 = 19,531
this is a geometric series where a₁=1 and r=5
Sn =a₁(qⁿ-1) / q-1
S7= 1*(5^7 -1)5-1 =>5^6/4 => 19531