Verified answer

6 tan(α)+9 = 7

6 tan(α) = -2

tan(α) = -2/6

tan(α) = -1/3

There are two α values between 0 αnd 2pi for which tan is negative.

α=tαn^-1(-1/3) = -0.3218 radian or 2pi-0.3218 = 5.9614 radian -----(1)

α = pi-0.3218 = 2.8198 radian -----(2)

6tan(a) +9 = 7

6tan(a) = -2

tan(a) = -1/3

6tan(α) + 9 = 7

6tan(α) = -2

tan(α) = -1/3

α = kπ + tan⁻¹(-1/3)

α = kπ - tan⁻¹(1/3), where k is any integer

For solutions on the given interval only, let k equal 1 or 2.

tan α = -1/3

α = 2.8198 or 5.9614 radians