r = 5; θ = -arctan(3/4)
r = sqrt(x°2+y°2)
r = sqrt( 4°2 + (-3)°2 ) = sqrt(16+9)= sqrt(25) = 5
θ = tan°-1(-3/4) =-36.87° = 360-36.87 = 323.13°
(r, θ) = (5, 323.13°)
r = 5
θ = 5.64
To the right 4, down 3. Length 5. Angle arctan(-3/4). Done.
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
Verified answer
r = 5; θ = -arctan(3/4)
r = sqrt(x°2+y°2)
r = sqrt( 4°2 + (-3)°2 ) = sqrt(16+9)= sqrt(25) = 5
θ = tan°-1(-3/4) =-36.87° = 360-36.87 = 323.13°
(r, θ) = (5, 323.13°)
r = 5
θ = 5.64
To the right 4, down 3. Length 5. Angle arctan(-3/4). Done.