Find all solutions of the equation. 6x^−2 + x^−1 = 2 [I don't know what to do with the negative exponents?]?
Find all solutions of the equation. 6x^−2 + x^−1 = 2 [I don't know what to do with the negative exponents?] So I'm having trouble doing this problem. Please explain. Thanks!
Answers & Comments
Verified answer
6x^−2 = 6 / x^2 and x^−1 = 1 / x --> (negative indicies put into fraction as positive indices in denominator)
so,
6/x^2 + 1/x = 2
(cross multiply)
x^2 + 6x = 2
x^2 + 6x - 2 = 0 --> so now its a quadratic
6x^â2 + x^â1 = 2
(6/x^2) + 1/x = 2
Multiply each term with x^2
6 + x = 2x^2
Reassembling the equation,
2x^2 - x - 6 = 0
2x^2 - 4x + 3x - 6 = 0
2x (x-2) + 3 (x-2) = 0
(2x+3) (x-2) = 0
Thus, either (2x+3) = 0 or (x-2) = 0
So, x = (-3/2) or x = 2
Hence the solution.