first, to be able to factorize this you should equate 10x² - 35x + 15= 0;
then factor out 5. You'll be left with. 5(2x^2-7x+3)0. In this case you could simply factor it out byinspection or better use the quadratic formula.The factored form for this quadratic equation is 5(2x-1)(x-3)=0;
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Verified answer
1. See if there is a common factor.
Yes, there is. it's 5.
Take that out like this:
5( 2x^2 - 7x + 3)
2. Now mid-term factorise the expression
2x^2 - 7x + 3
See 2*3 = 6
6+1=7
therefore,
2x^2 - 6x - x +3
Factorise this
2x(x - 3) - 1( x-3)
(2x-1)(x-3)
3.Put the thing together
5{ (2x - 1)( x - 3)}
You're done!
first, to be able to factorize this you should equate 10x² - 35x + 15= 0;
then factor out 5. You'll be left with. 5(2x^2-7x+3)0. In this case you could simply factor it out byinspection or better use the quadratic formula.The factored form for this quadratic equation is 5(2x-1)(x-3)=0;
10x^2 - 35x + 15
Factor out the Greatest Common Factor (GCF) = 5
5(2x^2 - 7x + 3)
Factor a trinomial
5(2x - 1) (x - 3)
Multiply using the FOIL Method to confirm (check and test) the answer.
2x x = 2x^2
2x x -3 = -6x
-1 x x = -1x
-1 x -3 = 3
2x^2 - 6x - 1x + 3
5(2x^2 - 7x + 3)
=> 10 x(square) - 30 x - 5 x +15
=> 10x[x-3] - 5[x-3]
=> [10x - 5][x-3]
So, x= 5/10 i.e 1/2 and x= 3 .. :) hope yu got it
Its 5(2x^2 -7x +3)=5(x-3)(2x-1)
5 (2x² - 7x + 3)
5 (2x - 1)(x - 3)
5(2*x2 - 7*x + 3)
5(2x2-6x-x+3)
5(2x(x-3)-(x-3))
5(2x-1)(x-1)
= 5(2X^2-7X+3)
=5(2X-1)(X-3)
The answer is 3.142
This is the Best Answer