Please show work! For some reason, I keep simplifying it down to 2 and I don't know how to make it in the form of a+b√3. Thanks!
1-(1/(1+ √3))+(1/(1- √3))
1 - (1 - √3)/(1 - √3)(1/(1 + √3) + (1 + √3)/(1 + √3)(1/(1 - √3)
1 - (1 - √3)/(1 - 3) + (1 + √3)/(1 - 3)
1 - (1 - √3)/(-2) + (1 + √3)/(-2)
Distribute the -1
1 +(-1+√3)/(-2) + (1 + √3)/(-2)
1+ (2√3)/(-2)
1+ -√3
The first answer's method is correct, though there's currently an arithmetic mistake in it:
1 - (1 - √3)/(1 - 3) + (1 + √3)/(1 - 3) =
1 - (1 - √3 + 1 + √3)/(-2)
should be
1 - (1 - √3 - 1 - √3)/(-2)
= 1 + (2√3)/(-2)
= 1 - √3
1 - (1 - √3)/(1 - √3)(1/(1 + √3) + (1 + √3)/(1 + √3)(1/(1 - √3) =
1 - (1 - √3 + 1 + √3)/(-2) =
1 + (2/2) =
2
I suppose it's in the form a + b√3 with a = 2 and b = 0.
idk
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Verified answer
1-(1/(1+ √3))+(1/(1- √3))
1 - (1 - √3)/(1 - √3)(1/(1 + √3) + (1 + √3)/(1 + √3)(1/(1 - √3)
1 - (1 - √3)/(1 - 3) + (1 + √3)/(1 - 3)
1 - (1 - √3)/(-2) + (1 + √3)/(-2)
Distribute the -1
1 +(-1+√3)/(-2) + (1 + √3)/(-2)
1+ (2√3)/(-2)
1+ -√3
The first answer's method is correct, though there's currently an arithmetic mistake in it:
1 - (1 - √3)/(1 - 3) + (1 + √3)/(1 - 3) =
1 - (1 - √3 + 1 + √3)/(-2)
should be
1 - (1 - √3)/(1 - 3) + (1 + √3)/(1 - 3) =
1 - (1 - √3 - 1 - √3)/(-2)
= 1 + (2√3)/(-2)
= 1 - √3
1 - (1 - √3)/(1 - √3)(1/(1 + √3) + (1 + √3)/(1 + √3)(1/(1 - √3) =
1 - (1 - √3)/(1 - 3) + (1 + √3)/(1 - 3) =
1 - (1 - √3 + 1 + √3)/(-2) =
1 + (2/2) =
2
I suppose it's in the form a + b√3 with a = 2 and b = 0.
idk