As a general rule, anything divided by ∞ is 0. Unless of course you have something like ∞/∞ which is undefined.
Let's look at 1/x for simplicity as the limit approaches ∞
1/1 = 1, not very close to 0
1/100 = .01, still not too close, be we can keep going
1/1000000 = .00000000001... as you can see, as the number gets smaller and smaller, we just keep adding more zeros. So, as the number will always increase in the denominator forever and be greater than the numerator of 1, it will continually approach 0. Now, does it actually equal 0? Yes and no. Theoretically yes it does and it is accepted that it does. But, we can not prove it without using series and other things. You can not "physically" see it, but it does indeed equal 0.
Eventually we would just have
.0000000000000000000000.... forever which is just 0.
when i say big, i mean bigger than anything in the universe. A number so big that a supercomputer will not even be able to calculate it's digits.
That number is in the denominator. That means you're gonna divide puny, weak, thin little "number eight" divided by the biggest baddest number in the universe? And you're confused as to why the answer will be close to zero?
Try this. divide 8 by 15 times 10
then put in your calculator 8/ 15 X 100
See what starts to happen?
try 8 / 15 X 10000000000
see what happens. Now imagine if that number had enough zeroes to reach the sun. How small do you think the answer is going to be? Here's another question, will the answer ever be negative? Or will it just keep approaching zero?
Answers & Comments
Verified answer
As a general rule, anything divided by ∞ is 0. Unless of course you have something like ∞/∞ which is undefined.
Let's look at 1/x for simplicity as the limit approaches ∞
1/1 = 1, not very close to 0
1/100 = .01, still not too close, be we can keep going
1/1000000 = .00000000001... as you can see, as the number gets smaller and smaller, we just keep adding more zeros. So, as the number will always increase in the denominator forever and be greater than the numerator of 1, it will continually approach 0. Now, does it actually equal 0? Yes and no. Theoretically yes it does and it is accepted that it does. But, we can not prove it without using series and other things. You can not "physically" see it, but it does indeed equal 0.
Eventually we would just have
.0000000000000000000000.... forever which is just 0.
If you mean 8/(15x) instead of 8/15x, then
lim 8/(15x) = 0
x-> â
because as a denominator approaches â or -â, the entire fraction tends towards 0.
1/2 > 1/3 > 1/4 > 1/5 > ... ~ 0
-1/2 < -1/3 < -1/4 < -1/5 < ... ~ 0
8/(the biggest number in the world)
when i say big, i mean bigger than anything in the universe. A number so big that a supercomputer will not even be able to calculate it's digits.
That number is in the denominator. That means you're gonna divide puny, weak, thin little "number eight" divided by the biggest baddest number in the universe? And you're confused as to why the answer will be close to zero?
Try this. divide 8 by 15 times 10
then put in your calculator 8/ 15 X 100
See what starts to happen?
try 8 / 15 X 10000000000
see what happens. Now imagine if that number had enough zeroes to reach the sun. How small do you think the answer is going to be? Here's another question, will the answer ever be negative? Or will it just keep approaching zero?