simple way is to divide the entire factor by utilizing x^2 and then enable x get relatively relatively massive so as that something like one million/x^2, one million/x or y/x^2 methods 0 (4x^2-y^2+8x-6y=9) /x^2 4 - (y/x) ^ 2 + 8/x - 6y/x^2 = 9 /x^2 4 - (y/x) ^ 2 + 0 - 0 = 0 (y/x) ^ 2 = 4 y/x = +/- 2 there is your slopes, and a few mathematicians probable hate me for doing it this way.
Answers & Comments
Verified answer
center is ( 2 , 3) so a = 4....symmetric about x = 2...thus
[ y - 3 ] ² / 4² - [ x - 2 ] ² / b² = 1 ; asymptotes are [ y - 3 ] = ± 4/b [ x - 2]...thus b = 7
simple way is to divide the entire factor by utilizing x^2 and then enable x get relatively relatively massive so as that something like one million/x^2, one million/x or y/x^2 methods 0 (4x^2-y^2+8x-6y=9) /x^2 4 - (y/x) ^ 2 + 8/x - 6y/x^2 = 9 /x^2 4 - (y/x) ^ 2 + 0 - 0 = 0 (y/x) ^ 2 = 4 y/x = +/- 2 there is your slopes, and a few mathematicians probable hate me for doing it this way.