Verified answer

(x-r)+x+(x+r)=6

3x=6

x=6/3

x=2

(x-r)*x*(x+r)=-10

,as x=2

(2-r)(2+r)=-10/2

4-r²=-5

-r³=-5-4

-r²=-9

r²=9

r=±3

para r=-3

(5,2,-1)

para r=3

(-1,2,5)

Tulaudero disse:

X-r,X,x+r

x-r+x+x+r=6

3x=6

x=2

(2-r).2.(2+r)=-10

2.(4-r^2)=-10

8-2r^2 =-10

-2r^2 = -10-8

-2r^2 = -18 . (-1)

2r^2 = 18

r^2 = 9

r=3

2-3,3,2+3

-1,2,5

PA

n - r, n, n+r

soma = n - r + n + n + r = 3n = 6

n = 2

(2-r)*2*(2+r) = -10

(2-r)*(2+r) = -5

4 - r² = -5

r² = 9

r = 3

PA

-1 , 2, 5