Determine the value of ∆G˚ for the following systems using your values for E˚.
Zn + Fe²⁺ → Zn²⁺ + Fe
Cu + Zn²⁺ → Cu²⁺ + Zn
The E˚ values that I have are the following:
Zn²⁺ + 2e¯ → Zn = -0.76v
Fe²⁺ + 2e¯ → Fe = -0.41v
Cu²⁺ + 2e¯ → Cu = +0.34v
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Verified answer
Hi Joey,
Zn + Fe²⁺ → Zn²⁺ + Fe
E = E˚(Fe) - E˚(Zn) + 0,06 • log([Zn²⁺] / [Fe²⁺] )
∆G˚ = 2 • F • ( E˚(Zn) - E˚(Fe) ) = 2 • 96500 • (- 0,76 + 0,41) = - 67550 J/mol
Cu + Zn²⁺ → Cu²⁺ + Zn
E = E˚(Cu) - E˚(Zn) + 0,06 • log([Zn²⁺] / [Cu²⁺] )
∆G˚ = 2 • F • ( E˚(Cu) - E˚(Zn) ) = 2 • 96500 • (0,34 + 0,76) = 212300 J/mol