Assuming the cubic function has rational coefficients, then the irrational roots are available pairs. (2 + ?3) is a root so (2 - ?3) is likewise a root. the factors are (x - 2 - ?3) and (x - 2 + ?3) and (x - a million). And a relentless. f(x) = A(x - 2 - ?3)(x - 2 + ?3)(x - a million) f(x) = A(x^3 - 5x^2 + 5x - a million) Fill interior the given element to locate a. 5 = A(2^3 - 5*2^2 + 5*2 - a million) A = -5/3
You need to explain better what you mean by order. Applying the usual interpretation, if a polynomial function has one root of order 3 and another of order 2, then the function must be of degree 5 or greater. It is not a cubic function.
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Assuming the cubic function has rational coefficients, then the irrational roots are available pairs. (2 + ?3) is a root so (2 - ?3) is likewise a root. the factors are (x - 2 - ?3) and (x - 2 + ?3) and (x - a million). And a relentless. f(x) = A(x - 2 - ?3)(x - 2 + ?3)(x - a million) f(x) = A(x^3 - 5x^2 + 5x - a million) Fill interior the given element to locate a. 5 = A(2^3 - 5*2^2 + 5*2 - a million) A = -5/3
You need to explain better what you mean by order. Applying the usual interpretation, if a polynomial function has one root of order 3 and another of order 2, then the function must be of degree 5 or greater. It is not a cubic function.