f(x) = y = mx + c
para m= 1/2, temos: y = x/2 + c
no ponto (2/3, 1):
1= (2/3)/2 + c
1 = 1/3 + c
c = 2/3
Assim a equação reduzida será: y = x/2 + 2/3
(y-1)=1/2(x-2/3)
2(y-1)=x-2/3
2y-2=x-2/3
x-2y+2-2/3=0
3x-6y+4=0
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
f(x) = y = mx + c
para m= 1/2, temos: y = x/2 + c
no ponto (2/3, 1):
1= (2/3)/2 + c
1 = 1/3 + c
c = 2/3
Assim a equação reduzida será: y = x/2 + 2/3
(y-1)=1/2(x-2/3)
2(y-1)=x-2/3
2y-2=x-2/3
x-2y+2-2/3=0
3x-6y+4=0