Ola Nayara
A(3, 0)
B(0, 8)
C(x, y)
m = (y - 8)/(x - 0) = (8 - 0)/(0 - 3)
(y - 8)/x = -8/3
3y - 24 = -8x
8x + 3y = 24
equação segmentaria
x/3 + y/8 = 1
pronto
y = ax + b => (3,0) => 3a + b = 0
(0,8) => b = 8 => 3a + 8 = 0 => a = -8/3 Portanto
y = (-8/3)x + 8
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Answers & Comments
Ola Nayara
A(3, 0)
B(0, 8)
C(x, y)
m = (y - 8)/(x - 0) = (8 - 0)/(0 - 3)
(y - 8)/x = -8/3
3y - 24 = -8x
8x + 3y = 24
equação segmentaria
x/3 + y/8 = 1
pronto
y = ax + b => (3,0) => 3a + b = 0
(0,8) => b = 8 => 3a + 8 = 0 => a = -8/3 Portanto
y = (-8/3)x + 8