sen x / cos sec x + cos x / sec x = 1
sen(x)/(cossec(x)) + cos(x)/sec(x) = 1
sen(x)/(1/sen(x)) + cos(x)/1/cos(x) = 1
sen²(x) + cos²(x) = 1
pronto
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
Verified answer
sen(x)/(cossec(x)) + cos(x)/sec(x) = 1
sen(x)/(1/sen(x)) + cos(x)/1/cos(x) = 1
sen²(x) + cos²(x) = 1
pronto