Since z = x + iy, this equals
∫c (x - iy) * (dx + i dy)
= ∫(x = 0 to 3) (x - ix^2) * (1 + i * 2x) dx, since y = x^2
= ∫(x = 0 to 3) (x + ix^2 + 2x^3) dx
= (x^2/2 + ix^3/3 + x^4/2) {for x = 0 to 3}
= 45 + 9i.
I hope this helps!
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Verified answer
Since z = x + iy, this equals
∫c (x - iy) * (dx + i dy)
= ∫(x = 0 to 3) (x - ix^2) * (1 + i * 2x) dx, since y = x^2
= ∫(x = 0 to 3) (x + ix^2 + 2x^3) dx
= (x^2/2 + ix^3/3 + x^4/2) {for x = 0 to 3}
= 45 + 9i.
I hope this helps!