Me ajudem, por favor... não consigo resolver!
x³ - 4x = x(x²-4) = x (x+2)(x-2)
2x² -6x -20 = 2(x² -3x -10) = 2(x+5) .(x-2)
x(x+2) . (x-2) / 2(x+5) . (x-2) = x(x+2) / 2(x+5)
x³-4x/2x²-6x-20=
x(x²-4)/x²-3x-10=
x(x+2)(x-2)/(x-5)(x+2)=
x(x-2)/(x-5)
x³-4x = x(x+2)(x-2)
2x²-6x-20 = 2(x²-3x-0) = 2(x-5)(x+2)
=======================
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
Verified answer
x³ - 4x = x(x²-4) = x (x+2)(x-2)
2x² -6x -20 = 2(x² -3x -10) = 2(x+5) .(x-2)
x(x+2) . (x-2) / 2(x+5) . (x-2) = x(x+2) / 2(x+5)
x³-4x/2x²-6x-20=
x(x²-4)/x²-3x-10=
x(x+2)(x-2)/(x-5)(x+2)=
x(x-2)/(x-5)
x³-4x = x(x+2)(x-2)
2x²-6x-20 = 2(x²-3x-0) = 2(x-5)(x+2)
=======================