Verified answer

A(x,1), B(4,x+3) C(x,x+2) e D(2x,x+6)

dAB² = (Ax - Bx)² + (Ay - By)²

dAB² = (x - 4)² + (1 - x - 3)²

dAB² = (x - 4)² + (x + 2)²

dAB² = x² - 8x + 16 + x² + 4x + 4 = 2x² - 4x + 20

dCD² = (Cx - Dx)² + (Cy - Dy)²

dCD² = (x - 2x)² + (x+2 - x - 6)²

dCD² = x² + 4² = x² + 16

2x² - 4x + 20 = x² + 16

x² - 4x + 4 = 0

(x - 2)² = 0

x = 2

pronto