-√2/2 - i√2/2 is on the unit circle at θ = 5π/4,
so (-√2/2 - i√2/2)³ is also on the unit circle, but at θ = 15π/4 which is 7π/4,
making (-√2/2 - i√2/2)³ = √2/2 - i√2/2
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-√2/2 - i√2/2 is on the unit circle at θ = 5π/4,
so (-√2/2 - i√2/2)³ is also on the unit circle, but at θ = 15π/4 which is 7π/4,
making (-√2/2 - i√2/2)³ = √2/2 - i√2/2