Having a little trouble with my calc hw right now. I'm a little rusty with finding indefinite integrals. Help please?
Let u = cot x. So du = -csc²x dx, and the integral becomes
∫ e^u (-du)
= - e^u + C
= - e^(cot x) + C.
I hope that helps!
=-e^(cotx) + costant
http://www.wolframalpha.com/input/?i=%C3%A2%C2%88%...
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Verified answer
Let u = cot x. So du = -csc²x dx, and the integral becomes
∫ e^u (-du)
= - e^u + C
= - e^(cot x) + C.
I hope that helps!
=-e^(cotx) + costant
http://www.wolframalpha.com/input/?i=%C3%A2%C2%88%...