If you mean log_2(8) then it goes like this:
log_2(8) = log_2(2^3) = 3*log_2(2) = 3*1 = 3.
where _ means "base"
?????
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If you mean log_2(8) then it goes like this:
log_2(8) = log_2(2^3) = 3*log_2(2) = 3*1 = 3.
where _ means "base"
?????