At O°C and 760 mm Hg, 28.0 g of nitrogen occupy 22.4 liters.?
How would I compute the mass of one liter of nitrogen at 35.0°C and 1500 mm Hg? Help, please.
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How would I compute the mass of one liter of nitrogen at 35.0°C and 1500 mm Hg? Help, please.
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PV = n R T and 28.0 g is one mole. n = mass/molar mass = mass/28
I'd probably do it by ratios
P1V1/P2V2 = m1 R T1 /m2 R T2 (I cancelled molar mass already,) Make the 1'a the new conditions
so 1500 x 1 / (750 x 22.4) = m1 x 309 / (28 x 273) so m1 = 1500 x 1 x 28 x 273/ (750 x 22.4 x 309)