Assuming that the value of ∆H and ∆S do not change with temperature, and using the following data,?
Assuming that the value of ∆H and ∆S do not change with temperature, and using the following data,
CaO(s), ∆Hfo = -635.5 KJ mol-1, So = +40.0 J mol-1 K-1
CaCO3(s), ∆Hfo = -1207 KJ mol-1, So = +92.9 J mol-1 K-1
CO2(g), ∆Hfo = -394 KJ mol-1, So = +213.6 J mol-1 K-1
Calculate the value for the free energy change, ∆Go for the reaction,
CaCO3(s) → CaO(s) + CO2(g) at 815oC
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OK....in a simple manner:
delta H = sum(Hf products) - sum (Hf reactants)
= (-635.5 + -394) - (-1207) = +177.5 kJ mol-1 = 177500 J mol-1
delta S = sum(S products) - sum(S reactants)
= (40 + 213.6) - 92.9 = 160.7 J mol-1 K-1
dG = dH - T*dS
= 177500 - ([815+273]*160.7) = 2658.4 J mol-1 = 2.66 kJ mol-1