a. 0 m
b. 2 m
c. 6 m
d. 3 m
distance moved =
integral of velocity from 0 to 2.0 seconds =
area of triangle with vertices (0,0), (2, 3), and (2, 0) =
base * height / 2 =
2 * 3 / 2 =
3m
Answer is (d).
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Answers & Comments
distance moved =
integral of velocity from 0 to 2.0 seconds =
area of triangle with vertices (0,0), (2, 3), and (2, 0) =
base * height / 2 =
2 * 3 / 2 =
3m
Answer is (d).