Verified answer

specific heat of water is 4.186 kJ/kgC

specific heat of ice is 2.06 kJ/kgC

specific heat of steam is 2.1 kJ/kgK

heat of fusion of ice is 334 kJ/kg

heat of vaporization of water is 2256 kJ/kg

steam at 100ºC ?

10.6 cm³ = 10.6e-6 m³ = 0.0106 kg

add up the numbers

to warm ice to 0º

E1 = 2.06 kJ/kgC x 0.0106 kg x 12C

to melt ice

E2 = 334 kJ/kg x 0.0106 kg

to heat water to 100º

E3 = 4.186 kJ/kgC x 0.0106 kg x 100C

to boil water

E4 = 2256 kJ/kg x 0.0106 kg

edit, corrected mistake.

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