C. is located at the point (x, y, z) = (0, 1 cm, 0) while the negative charge is located at the point (x, y, z) = (0, -1 cm, 0). How much work will be done by an electric field E = (3 × 106 N/C ) i hat to bring the dipole to its stable equilibrium position?
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Verified answer
Distance between the two charges is d = 2 cm = 0.02m
Work needed = qEd = 1.e-6*3e6*0.02 = 0.06 J
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