An arteriole has a length of 1.03 mm and a radius of 24.7 μm. The blood pressure drop along the arteriole is 1?

An arteriole has a length of 1.03 mm and a radius of 24.7 μm. The blood pressure drop along the arteriole is 1690 Pa.

a)Calculate the resistance of the arteriole. (assume body temperature)

b) Calculate the flow rate through the arteriole.

c) Calculate the number of arterioles like this one you would need to maintain a flow of 2.91e-06 m^3/s

my working i tried my best but still couldn't figure it out

help me please

I tried but its still wrong!!

Length L = 1.03 mm = 0.00103 m Radius r = 24.7 u m = 24.7 * 10^-6 m

The resistance to the flow is given by poiseulli equation R = ( 8 * mu * L ) / ( pi * r^4 ) so R = ( 8 * 4 * 1.03 * 10^-6 ) / ( pi * (24.7 * 10^-6 )^4)

so R = 2.8187 * 10^13 ohm

flow rate = pressure / resistance = 1690 / ( 2.8187 * 10^13 ) = 5.99567 * 10^-11 m^3 / sec

no. of arterioles = total flow rate / flow rate of one arteriole = (2.91* 10^-6) / ( 5.99567 * 10^-11 ) no. of arterioles = 48535.0118

show me right one please. Thanks people

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