What is the question?
number of moles of Helium 4.94*10^4L= 49.4m^3
pV= nRT n=pV/RT= 0.995*101325*49.4/(8.314*305)=1964 moles of Helium
in mass 6439g since 1 mole =4.003g
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Verified answer
What is the question?
number of moles of Helium 4.94*10^4L= 49.4m^3
pV= nRT n=pV/RT= 0.995*101325*49.4/(8.314*305)=1964 moles of Helium
in mass 6439g since 1 mole =4.003g