A submarine dives 96 m at an angle of 10° below the horizontal. What are the two components?
x=m
y=m
y component----> 96sin10=16.7
x component----->96cos10=94.5
Angle theta-------->tan^-1(y/x)
tan^-1 (16.7/94.5)=9.9 degrees.
x=m 96 * SIN 10
y=m 96 * COS 10
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y component----> 96sin10=16.7
x component----->96cos10=94.5
Angle theta-------->tan^-1(y/x)
tan^-1 (16.7/94.5)=9.9 degrees.
x=m 96 * SIN 10
y=m 96 * COS 10