The vigour of a single photon is: E = hf = hc / lambda So the energy is: P = E/t= hc / lambda * number of photons / time clear up for the photon price: N/t = P lambda / hc They provide the energy and wavelength. Look up planck's constant (h) and the speed of light (c). Or just memorize their product, which in general comes up--hc = 1240 eV-nm. What do not you fully grasp? The derivation? Or do not you know the way to plug in the given energy and wavelength, multiply them, and divide by using hc, which I gave you?
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Photon energy is proportional to frequency, so inversely proportional to wavelength.
So the longer wavelength must have more photons to achieve the same power, or energy per second.
The question is easier than it looks.
The vigour of a single photon is: E = hf = hc / lambda So the energy is: P = E/t= hc / lambda * number of photons / time clear up for the photon price: N/t = P lambda / hc They provide the energy and wavelength. Look up planck's constant (h) and the speed of light (c). Or just memorize their product, which in general comes up--hc = 1240 eV-nm. What do not you fully grasp? The derivation? Or do not you know the way to plug in the given energy and wavelength, multiply them, and divide by using hc, which I gave you?