A diver exhales a bubble with a volume of 250 mL at a pressure of 2.4 atm and a temperature of 15 °C.?
A diver exhales a bubble with a volume of 250 mL at a pressure of 2.4 atm and a temperature of 15 °C.
HOW MANY GAS PARTICLES ARE IN THIS BUBBLE?
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PV = nRT
n = PV/RT = (2.4 atm) × (0.250 L) / ((0.08205746 L atm/ K mol) × (15 + 273 K)) = 0.025 mol
(0.025 mol) × (6.02 × 10^23 gas particles/mol) = 1.5 × 10^22 gas particles