A chemist assembles an electrochemical cell based on the reaction: 2 Fe(s) + 3 Ni2+(aq) 2 Fe3+(aq) + 3?
4) A chemist assembles an electrochemical cell based on the reaction:
2 Fe(s) + 3 Ni2+(aq) 2 Fe3+(aq) + 3 Ni(s)
• Give the half reaction at the cathode
• Calculate the value of the standard cell potential at 25ºC.
Fe3+ + 3e- Fe E°=-0.037v
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Reduction happens at the cathode (RED CAT) oxidation at the anode (ANOX).
LEO says GER (losing electrons is oxidation, gaining electrons is reduction)
Half reaction at the cathode: Ni2+ + 2e- --> Ni
Ni2+ + 2e- --> Ni E=-0.23
Fe --> Fe3+ + 3e- E = 0.037 (The sign is changed because the equation is flipped.)
Now add the cell potentials = -0.19 V
Hope that helps.
For E 0 write the two a million/2 reactions and seem up their voltages, then upload voltages at the same time. Al yields Al+3 plus 3 e, voltage + a million.sixty seven volts Co+2 plus 2e yields Co -.28 extra at the same time = +l.39 volts.