A charge of -2.95 µC is fixed at the center of a compass.?
A charge of -2.95 µC is fixed at the center of a compass. Two additional charges are fixed on the circle of the compass, which has a radius of 0.108 m. The charges on the circle are -3.95 µC at the position due north and +4.50 µC at the position due east. What are the magnitude and direction of the net electrostatic force acting on the charge at the center? Specify the direction relative to due east.
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north charge pushes center charge "south":
Fy = k*q1*q2 / r² = 8.99e9 N·m²/C² * -2.95e-6C * -3.95e-6C / (0.108m)² = 9 N south
east charge pulls center charge "east"
Fx = 10.2 N east
mag F = √(9² + 10.2²) N = 13.6 N
Θ = arctan(-9/10.2) = -41º = 41º S of E, or 319º ccw from east