x - 12y = -210
x - 6y = 90
6y = 300
x = 390
-
x - 12y = - 210
x - 6y = 90_______subtract
- 6y = - 300
y = 5
x - 30 = 90
x = 120
subtract equation 1 from equation 2,
__________
-6y = -300
Divide both sides by -6. To get
y = 50
Substitute y = 50 into any of the two equations,
x - 12(50) = -210
If x - 12y = -210 and x - 6y = 90,
then x = (-210×-6--12×90)/(1×-6--12×1) = 2340/6 = 390
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Answers & Comments
x - 12y = -210
x - 6y = 90
6y = 300
x = 390
-
x - 12y = - 210
x - 6y = 90_______subtract
- 6y = - 300
y = 5
x - 30 = 90
x = 120
subtract equation 1 from equation 2,
x - 12y = -210
-
x - 6y = 90
__________
-6y = -300
Divide both sides by -6. To get
y = 50
Substitute y = 50 into any of the two equations,
x - 12y = -210
x - 12(50) = -210
x = 390
If x - 12y = -210 and x - 6y = 90,
then x = (-210×-6--12×90)/(1×-6--12×1) = 2340/6 = 390