A charge of 2.400×10-8 C lies on an isolated metal sphere of radius 15 cm. With V = 0 at infinity?
A charge of 2.400×10-8 C lies on an isolated metal sphere of radius 15 cm. With V = 0 at infinity, what is the electric potential at points on the sphere's surface?
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Outside of the sphere itself, spherical charge distributions behave identically to point charges. Hence, we are able to use the formula V = kq/r to determine the potential.
V = (8.988 x 10^9)(2.400 x 10^(-8))/(0.15 meters)
= 1.438 x 10^3 V
locate quantity of metallic 24/8000 m^3 for this reason radius and then diameter same quantity is going into the cone, much less 15% = 0.80 5 * unique quantity locate top of cone utilising that quantity and radius of base