A car is parked on a cliff overlooking the ocean on an incline that makes an angle of 23.0° below the horizontal. The negligent driver leaves the car in neutral, and the emergency brakes are defective. The car rolls from rest down the incline with a constant acceleration of 3.67 m/s2 for a distance of 35.0 m to the edge of the cliff, which is 30.0 m above the ocean.
(a) Find the car's position relative to the base of the cliff when the car lands in the ocean.
m
(b) Find the length of time the car is in the air.
s
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
Verified answer
Velocity at the end of the incline is given by the equations
v = 3.67*t and v^2 = 2*3.67*35
v = 16.03 m.s and t = 4.37 s
------------------------------
At the end of the cliff its horizontal speed is
16.03 cos 23° and its vertical speed is 16.03 sin 23°
Time to fall vertically a distance of 35 m is given by
35 = 16.03*t * sin 23° + 4.9 t²
t = 2.1089 s
and the horizontal distance traveled in tbis time is
16.03 sin 23 *2.1089 = 13 .2 m
=======================
Total time in air = 4.37 + 2.1089 = 6.48 s
========================
I. Have. No. Idea. O.o