A 50 N crate slides down an inclined plane raised 15° above the horizontal. What force does the inclined plane exert on the crate?
well, the crate is being pulled down with MG, correct? well FN would be the incline pushing on the crate?
but since it is on an angle, FN= mgcos(15) as it is the vertical component of gravity that is pushing against the incline, not the horizontal.
so
mg=FN
50(cos15)= FN
FN= 48.3N
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well, the crate is being pulled down with MG, correct? well FN would be the incline pushing on the crate?
but since it is on an angle, FN= mgcos(15) as it is the vertical component of gravity that is pushing against the incline, not the horizontal.
so
mg=FN
50(cos15)= FN
FN= 48.3N