A 2.5L sample of gas at 23.0°C...?
A 2.5-L Sample of gas at 23.0°C and 0.995 atm pressure was heated to 39.5°C and the pressure was raised to 1.48 atm. What was the final volume of the gas?
A. 1.7 L
B. 2.6 L
C. 1.8 L
D. 3.5 L
Please help and explain for me thank you
More Questions From This User See All
Answers & Comments
Verified answer
P1V1/T1 = P2V2/T2
P1 = 0.995
V1 = 2.5
T1 = 23 + 273 = 296
P2 = 1.48
V2 = ?
T2 = 39.5 + 273 = 312.5
0.995 x 2.5 / 296 = 1.48 x V2 / 312.5
0.0084 = 0.0047 V2
V2 = 0.0084 / 0.0047 = 1.78L or 1.8L
Answer is C
Use P1V1/T1 = P2V2/T2
P1 = 0.995 at
V1 = 2.5 L
T1 = 23 + 273 = 296 K
P2 = 1.48 atm
V2 = ?
T2 = 39.5 + 273 = 312.5
P1V1/T1 = P2V2/T2 and solving for V2 you get P1V1T2/P2T1 = (0.995)(2.5)(312.5)/(1.48)(296) = 1.77 1.8L
ANSWER should be C. 1.8 L